Q.

A point charge 2×102 C is moved from P to S in a uniform electric field of 30NC1directed along Positive x- axis .If coordinates of P and S are (1, 2, 0) m and (0, 0, 0) m respectively, the work done by electric field will be

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a

600 mJ

b

-600 mJ

c

– 1200 mJ

d

1200 mJ

answer is C.

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Detailed Solution

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Work done, W=FS where
F=qE=2×102×30i^=0.6i^
And S=r2r1=0(i^+2j^)=(i^+2j^)
 So W=FS=0.6i^(i^2j^)=0.6J=600mJ

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