A point like object is placed at a distance of 1m in front of a convex lens of focal length 0.5 m. A plane mirror is placed at a distance of 2m behind the lens. The position and nature of the final image formed by the system is :

$\begin{array}{l}Lens Formula, \text{}\\ \frac{1}{v_1}-\frac{1}{\left(-1\right)}=\frac{1}{0.5}\text{}\\ \Rightarrow v_1=1m \\ Now, I_1 will act like object for plane mirror.\text{}\\ So, I_2 will be formed 1m behind the mirror. \text{}\\ Now, I_2 will act like object for convex lens.\\ Lens formula, \\ \text{} \frac{1}{v_3}-\frac{1}{\left(-3\right)}=\frac{1}{0.5}\text{}\\ \Rightarrow v_3=\frac{3}{5}m\\ So, real image I_3 is formed at 0.6 m on left of lens or 2.6m from mirror. \end{array}$