A point object is placed at a distance of 20cm from a glass slab (μg=32) half immersed in water (μω=43) as shown in fig. the distance between two images when seen from the other side of the slab is

(shift)2=t(1−μωμg)=9(1−89)=1cm (shift)1=t(1−1μg)=9(1−13/2)=3cmSo, distance between two images is given by (shift)1−(shift)2=2cm

A point object is placed at a distance of 20cm from a glass slab (μg=32) half immersed in water (μω=43) as shown in fig. the distance between two images when seen from the other side of the slab is

(shift)2=t(1−μωμg)=9(1−89)=1cm (shift)1=t(1−1μg)=9(1−13/2)=3cmSo, distance between two images is given by (shift)1−(shift)2=2cm

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A point object is placed at a distance of 20cm from a glass slab $(μ_{g} = \frac{3}{2})$ half immersed in water $(μ_{ω} = \frac{4}{3})$ as shown in fig. the distance between two images when seen from the other side of the slab is

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2cm

4cm

6cm

1cm

answer is B.

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${(s h i f t)}_{2} = t (1 - \frac{μ_{ω}}{μ_{g}}) = 9 (1 - \frac{8}{9}) = 1 c m {(s h i f t)}_{1} = t (1 - \frac{1}{μ_{g}}) = 9 (1 - \frac{1}{3 / 2}) = 3 c m$

So, distance between two images is given by ${(s h i f t)}_{1} - {(s h i f t)}_{2} = 2 c m$

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A point object is placed at a distance of 20cm from a glass slab (μg=32) half immersed in water (μω=43) as shown in fig. the distance between two images when seen from the other side of the slab is

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A point object is placed at a distance of 20cm from a glass slab $(μ_{g} = \frac{3}{2})$ half immersed in water $(μ_{ω} = \frac{4}{3})$ as shown in fig. the distance between two images when seen from the other side of the slab is