A point object is placed at equal distance ‘3f' in-front of a concave mirror, a convex mirror and a plane mirror separately (event-1). Now, the distance is decreased to ‘1.5f’ from all the three mirrors similarly( event-2). Magnitude of focal length of convex mirror and concave mirror is ‘f’. Then choose the correct options.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

Maximum distance of image from the mirror in event-1 is for plane mirror

Maximum distance of image from the mirror in event-2 is for concave mirror

Minimum distance of image from the mirror in event-2 is for plane mirror

Minimum distance of image from the mirror in event-1 is for convex mirror

answer is A, B, C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

In event -1
For concave mirror, $\frac{1}{v} + \frac{1}{- 3 f} = \frac{1}{- f}$

$∴ v = - 1.5 f$

For convex mirror,

$\frac{1}{v} + \frac{1}{- 3 f} = \frac{1}{+ f} v = \frac{3}{4} f = 0.75 f$

For plane mirror, $v = + 3 f$

Inevent-2
For concave mirror,

$\frac{1}{v} + \frac{1}{- 1.5 f} = \frac{1}{- f}$

$∴ v = - 3 f$

For convex mirror,

$\frac{1}{v} + \frac{1}{- 1.5 f} = \frac{1}{+ f} ∴ v = \frac{3 f}{5} = 0.6 f$

For plane mirror, $v = + 1.5 f$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE