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A point object is placed on the axis of a concave mirror of focal length $24 c m$ such that the image is formed at a distance of $48 c m$ from the pole. Distance of the object from pole may be

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20 cm

48 cm

32 cm

16 cm

answer is A, B.

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Detailed Solution

$f = - 24 c m v = 48 c m u = ?$

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f} \frac{1}{u} = \frac{1}{f} - \frac{1}{v} \frac{1}{u} = \frac{1}{- 24} \pm \frac{1}{48} = \frac{- 2 \pm 1}{48} = \frac{- 1}{48}, \frac{- 3}{48} \Rightarrow u = - 48 c m o r - 16 c m$

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