A point object, ‘O’ is placed in front of two thin symmetrical coaxial convex lenses L₁ and L₂ with focal length 24 cm and 9 cm respectively. The distance between two lenses is 10cm and the object is placed 6 cm away from lens L₁ as shown in the figure. The distance between the object and the image formed by the system of two lenses is…….cm

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

answer is 34.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$For L_{1}, u = - 6 cm, f = 24 cm \begin{array}{l} \frac{1}{v} - \frac{1}{- 6} = \frac{1}{24} (Lens formula) \\ \frac{1}{v} = \frac{1}{24} - \frac{1}{6} \Rightarrow v = - 8 cm \\ for L_{2}, u = - (10 + 8) = - 18 cm \\ f = 9 cm \\ \frac{1}{v} - \frac{1}{- 18} = \frac{1}{9} \Rightarrow \frac{1}{v} = \frac{1}{9} - \frac{1}{18} \\ \Rightarrow v = 18 cm \end{array}$
Hence final image is formed at the distance of 18cm from L₂.
$OI = 6 cm + 10 cm + 18 cm = 34 cm$