A point object, ‘O’ is placed in front of two thin symmetrical coaxial convex lenses L₁ and L₂ with focal length 24 cm and 9 cm respectively. The distance between two lenses is 10cm and the object is placed 6 cm away from lens L₁ as shown in the figure. The distance between the object and the image formed by the system of two lenses is…….cm

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 34.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$For L_{1}, u = - 6 cm, f = 24 cm \begin{array}{l} \frac{1}{v} - \frac{1}{- 6} = \frac{1}{24} (Lens formula) \\ \frac{1}{v} = \frac{1}{24} - \frac{1}{6} \Rightarrow v = - 8 cm \\ for L_{2}, u = - (10 + 8) = - 18 cm \\ f = 9 cm \\ \frac{1}{v} - \frac{1}{- 18} = \frac{1}{9} \Rightarrow \frac{1}{v} = \frac{1}{9} - \frac{1}{18} \\ \Rightarrow v = 18 cm \end{array}$
Hence final image is formed at the distance of 18cm from L₂.
$OI = 6 cm + 10 cm + 18 cm = 34 cm$

Watch 3-min video & get full concept clarity

tricks from toppers of Infinity Learn

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

🔥 Start Your JEE/NEET Prep at Just ₹1999 / month - Limited Offer! Check Now!

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET