A point object, ‘O’ is placed in front of two thin symmetrical coaxial convex lenses L₁ and L₂ with focal length 24 cm and 9 cm respectively. The distance between two lenses is 10cm and the object is placed 6 cm away from lens L₁ as shown in the figure. The distance between the object and the image formed by the system of two lenses is…….cm

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 34.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$For L_{1}, u = - 6 cm, f = 24 cm \begin{array}{l} \frac{1}{v} - \frac{1}{- 6} = \frac{1}{24} (Lens formula) \\ \frac{1}{v} = \frac{1}{24} - \frac{1}{6} \Rightarrow v = - 8 cm \\ for L_{2}, u = - (10 + 8) = - 18 cm \\ f = 9 cm \\ \frac{1}{v} - \frac{1}{- 18} = \frac{1}{9} \Rightarrow \frac{1}{v} = \frac{1}{9} - \frac{1}{18} \\ \Rightarrow v = 18 cm \end{array}$
Hence final image is formed at the distance of 18cm from L₂.
$OI = 6 cm + 10 cm + 18 cm = 34 cm$