A point source of light B is placed at a distance L in front of the centre of a mirror of width d hung vertically on a wall. A man walks in front of the minor along a line parallel to the mirror at a distance 2 L from it as shown. The greatest distance over which he can see the image of the light source in the mirror is

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d/2

answer is D.

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Detailed Solution

According to the following ray diagram HI = AB = d

$\begin{array}{l} and DS = CD = \frac{d}{2} \\ ∵ Ah = 2 AD \Rightarrow GH = 2 CD = \frac{2 d}{2} = d \\ similarly IJ = d so GJ = GH + HI + IJ = d + d + d = 3 d \end{array}$

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