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A point source of light B, placed at distance L infront of the centre of the plane mirror of width d, hangs vertically on the wall. A man walks infront of the mirror along the line parallel to the mirror at distance 3L from it. The greatest distance over which he can see the image of the light.

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answer is A.

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Detailed Solution

Distance he can observe $= L [1 + \frac{P}{d}]$

Here length of the mirror L = d

Distance d = L

Distance from the mirror P = 3L

$x = d [1 + \frac{3L}{L}]$

$x = 4 d$

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