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Q.

A point source of light is placed 4 m below the surface of water of refractive index 5/3. The minimum diameter of a disc, which should be placed over the source, on the surface of water to cut – off all light coming out of water is :

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a

1 m

b

4 m

c

3 m

d

6 m

answer is D.

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Detailed Solution

Here

$\sin i = \frac{1}{μ} = \frac{3}{5}$

And hence

$tani = \frac{3}{4} = \frac{r}{4}$

This gives r = 3 m, hence diameter = 6 m

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A point source of light is placed 4 m below the surface of water of refractive index 5/3. The minimum diameter of a disc, which should be placed over the source, on the surface of water to cut – off all light coming out of water is :