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A point source of light $S$ is placed in front of a perfecting mirror as shown in the figure $S^{'}$ is a screen the intensity at the centre of the screen is found to be $I$ . If the mirror is removed then the intensity at the centre of the screen would be

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$\frac{9 I}{10}$

$2 I$

$I$

$\frac{10 I}{9}$

answer is C.

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Detailed Solution

Let power of light source be $P,$ then intensity at any point on the screen is due to light rays directly received from source and that due to after reflection from the mirror

$I = \frac{p}{4 π a^{2}} + \frac{p}{4 π \times {(3 a)}^{2}} = \frac{p}{4 π a^{2}} \times \frac{10}{9}$

When mirror is taken away

$I_{1} = \frac{p}{4 π a^{2}} = \frac{9 I}{10}$

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