A point source of light, S is placed at a distance L in front of the center of plane mirror of width d which is hanging vertically on a wall. A man walks in front of the mirror along a line parallel to the mirror, at a distance 2L as shown below. The distance over which the man can see the image of the light source in the mirror is:

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d/2

answer is C.

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Detailed Solution

The ray diagram is as follows:
From figure, WX = PQ = d

$ZS = RS = \frac{d}{2}$
$\begin{array}{l} ∵ PW = 2 PS \\ ∴ VW = 2 RS = 2 \frac{d}{2} = d \\ Similarly, XY = d \\ ∴ VY = VW + WX + XY = d + d + d = 3 d \end{array}$

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