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A pole $10 m$ high cast a shadow $10 m$ long on the ground, then find the sun’s elevation.

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60^{\circ}

45^{\circ}

30^{\circ}

90^{\circ}

answer is B.

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Detailed Solution

Given,
Pole height AB= 10 m,
Cast a shadow AC= 10 m.
Question Image

△ BAC

we have,

\tan θ = \frac{AB}{BC}

\tan θ = \frac{10}{10}

\tan θ = 1

\tan θ = \tan 45^{o}

On comparing we get,

\Rightarrow θ = 45^{\circ}

So, sun's angle of elevation

θ = 45^{\circ}

.
Hence, the option 2 is correct.

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