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A pole 6 m high casts a shadow $2 \sqrt{3}$ m long on the ground, then the sun's elevation is

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60^{0}

45^{0}

30^{0}

90^{0}

answer is A.

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Detailed Solution

It is given that a pole 6 m high casts a shadow

2 \sqrt{3}

m long on the ground.
Question Image

The sun's elevation angle will be opposite to the side which depicts the height of the pole, and base will be the length of the shadow.
Let

θ

be the angle of elevation.
Base =

2 \sqrt{3} m

Height =

6 m

Now,

tanθ = \frac{6}{2 \sqrt{3}}

.
⇒

tanθ = \sqrt{3}

⇒

θ = \tan^{- 1} (\sqrt{3})

⇒

θ = 60^{0}

Hence, the correct option is 1.

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