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A pole 6 m high casts a shadow $23$ m long on the ground, then the Sun's elevation is

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45 °

60 °

30 °

90 °

answer is A.

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Detailed Solution

Given that a pole 6 m high casts a shadow

23

m long on the ground.
Question Image

We know,

tanθ = \frac{Perpendicular}{Base}

\tan 60 ° = \sqrt{3}

Let

θ

be the elevation.
Therefore in triangle ABC,

tanθ = \frac{AB}{AC}

\Rightarrow tanθ = \frac{6}{2 \sqrt{3}}

\Rightarrow tanθ = \sqrt{3}

\Rightarrow tanθ = \tan 60 °

\Rightarrow θ = 60 °

Therefore, the Sun’s elevation is

600

.
Therefore, option 1 is correct.

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