A police jeep is chasing with velocity of $45 {\mathrm{kmh}}^{-1}$, a thief in another jeep moving with velocity $153 {\mathrm{kmh}}^{-1}$. Police fires a bullet with muzzle velocity of $180 {\mathrm{ms}}^{-1}$. The velocity with which it will strike the car of the thief is [EAMCET 2014]

Let v_PG = velocity of police w.r.t. ground,
      v_TG = velocity of thief w.r.t. ground,.
      v_TP = velocity of thief w.r.t. police $={\mathrm{v}}_{\mathrm{TG}}-{\mathrm{v}}_{\mathrm{PG}}$

             $=\left(\frac{153-45}{18}\right)\times 5=30{ \mathrm{ms}}^{-1}$

      v_BC = velocity of bullet w.r.t. car
             = 180 $-$ 30 = $150 {\mathrm{ms}}^{-1}$