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Q.

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A poly-atomic molecule (Cv=3R,Cp=4R, where R is gas constant) goes from phase space point A(PA=105Pa,VA=4×106m3) to point B to point B (PB=5×104Pa, VB=6×106m3) to point C(PC=104 Pa, VC=8×106m3) A to B is an adiabatic path and B to C is an isothermal path. The net heat absorbed per unit mole by the system
is :

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a

400R ln4

b

500R ln2

c

500R(ln3 + ln4)

d

450R(ln4 – ln3)

answer is B.

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Detailed Solution

 ΔQAB=0 (adiabatic) ΔQBC=ΔWBC =nRTln(VCVB)=450Rln(8×1066×106) =450Rn(43)=450R(ln4n3) ΔQ=ΔQAB+ΔQBC ΔQ=450R(n4n3)

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