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Q.

A polyatomic gas with n degrees of freedom has a mean energy per molecule given:

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a

3kT/2

b

nkT/2

c

nkT/N

d

nkT/2 N

answer is C.

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Detailed Solution

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K.E. per degree of freedom =12kT

For polyatomic gas, mean K.E. =  nkT2

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A polyatomic gas with n degrees of freedom has a mean energy per molecule given: