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Q.

A polyatomic gas with n degrees of freedom has a mean energy per molecule given:

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a

nkT/N

b

nkT/2 N

c

nkT/2

d

3kT/2

answer is C.

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Detailed Solution

K.E. per degree of freedom =12kT

For polyatomic gas, mean K.E. =  nkT2

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