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A ‘pop’ gun consists a tube 25cm long closed at one end by a cork and the other end by a tightly fitted piston as shown. The piston is pushed slowly in. When the pressure rises to one and half times the atmospheric pressure, the cork is violently blow out. The frequency of the ‘pop’ caused by its ejection is

$(V = 340 m / s)$

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Detailed Solution

$n = \frac{V}{4 l^{1}} p^{1} l^{1} = p l 1.5 p l^{1} = p \times 25 \times 10^{- 2}$

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