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A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele ‘A’ 0.7, genotype frequency of ‘Aa’ is

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0.21

0.42

0.36

0.7

answer is B.

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Detailed Solution

p + q = 1

Allele 'A' : p = 0.7

Allele ‘a’ : q = 1 $-$ 0.7 = 0.3

‘Aa’ : 2pq = 2 $\times$ 0.7 $\times$ 0.3 = 0.42

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