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Q.

A porter lifts a heavy suitcase of mass 80 kg and at the destination lowers it down by a distance of 80 cm with a constant velocity. Calculate the workdone by the porter in lowering the suitcase. (take g = 9.8 ms–2)

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a

+627.2 J

b

–62720.0 J

c

–627.2 J

d

784.0 J

answer is D.

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Detailed Solution

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Because the luggage is being lowered at a steady speed, there is no net force.

Net force = 0

Fext=mg

Work done=Fextscos180

=mg×s×-1=80×9.8×0.8×-1=-627.2J

Hence the correct answer is -627.2J.

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