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Q.

A positive charge of q1 is located 3 m to the left of a negative charge -q2. Magnitude of charge q1 greater than magnitude of negative charge q2. The net electric field intensity is zero at a point on the line passing through charges and 1 m to the right of -q2. On this line there are also points where the potential is zero. Location of these two points relative to the negative charge is/are

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a

 at 0.2 m left of negative charge

b

 at 317 m right of negative charge

c

at 0.2 m right of negative charge

d

at 317 m left of negative charge

answer is B, C.

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Detailed Solution

Question Image

 

kq212=kq116 q1=16q2

Potential can be zero both inside and outside the if on the line joining then

For a point P lying outside the two charges

Question Image

 

Vat P=0 -kq2x+kq13+x=0

  +q2x=16q23+x   3+x=16x   3=15x   x=15=0.2 m For  a  point  P  lying  between  the  charges  Vat P=0

Question Image

 

  kq13-x=kq2x   16x=3-x   x=317 meter 

 

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