A positive charge q is placed in front of a conducting solid cube at a distance d from its centre. Find the electric field at the centre of the cube due to the charges appearing on its surface.

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$\frac{q}{4 {πε}_{0} d^{2}} towards the charge q$

$\frac{q}{4 {πε}_{0} d^{2}} away from charge q$

Zero

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answer is A.

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Detailed Solution

Electric field at C due to q:

$E = \frac{kq}{d^{2}}, away from q$

As net field at C is zero, so field at C due to induced charges should be opposite to E.

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