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Q.

A positively charged particle having charge q and mass m enters in isosceles right angle triangular region having uniform magnetic field B as shown in gravity free space. The maximum value of v so that particle must comes out through the region from side PQ is

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a

( 2 −1)BqL 2m    

b

BqL 2 2 m  

c

(2−1)BqLm 

d

BqL 2 m  

answer is B.

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Detailed Solution

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For v to be maximum the line x+y=L  must be tangent to the circle 
x 2 + (y−R) 2 = R 2  

Hence R=(2−1)L

Vmax=(2−1)LBqm   

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