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A Positron and a Proton are accelerated by the same accelerating potential. Then the ratio of the associated wavelengths of the Positron and the Proton will be
[M = Mass of Proton, m = Mass of Positron]

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$\frac{m}{M}\$

$\sqrt {\frac{m}{M}} \$

$\sqrt {\frac{M}{m}} \$

$\frac{M}{m}\$

answer is B.

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Detailed Solution

                         q mass
   Positron +e      m
   Proton       +e      M

$\lambda = \frac{h}{{\sqrt {2mVq} }}\therefore \lambda \alpha \frac{1}{{\sqrt m }}\$

$\therefore \frac{{{\lambda _{positron}}}}{{{\lambda _{proton}}}} = \sqrt {\frac{{{m_{proton}}}}{{{m_{positron}}}}} \,\,\,\,= \sqrt {\frac{M}{m}}$

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