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Q.

A pot-maker rotates pot-making wheel of radius 3 m by applying a force of 200 N tangentially; because of this if wheel completes exactly 1½ revolution, the work done by him is

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a

4321.32 J 

b

5000 J

c

4197.5 J 

d

5657.86 J  

answer is A.

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Detailed Solution

work done in rotational motion is  here 

Work done in rotational motion is τθ

here τ= 200 x3

θ= 1.5×2π

W=600×3π≃5657.86J

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