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A potential barrier V volts exists across a P-N junction. The thickness of depletion region is ‘d’. An electron with velocity v approaches the junction from N-side. The velocity of the electron crossing the junction is

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$\sqrt{v^{2} + \frac{2 V e}{m}}$

$\sqrt{v^{2} - \frac{2 V e}{m}}$

$v$

$\sqrt{\frac{2 V e}{m}}$

answer is B.

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Detailed Solution

Electron looses energy as it goes along the

fields

$\frac{1}{2} m V_{1}^{2} = \frac{1}{2} m v^{2} - e V$

$∴ V^{1} = \sqrt{v^{2} - \frac{2 e V}{m}}$

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