A potential difference is applied between the ends of a conductor of uniform radius 1.5 mm. It results in an electric field of strength 250 V/m along the length of conductor. Find the resistivity of the material if current in the conductor is 2A.

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$12 π \times 10^{- 4} Ω - m$

$8 .83 \times 10^{- 4} Ω - m$

$25 π \times 10^{- 4} Ω - m$

$4 π \times 10^{- 4} Ω - m$

answer is A.

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Detailed Solution

$j = \frac{i}{A} = \frac{2}{π {(1.5 \times 10^{- 3})}^{2}} = \frac{8 \times 10^{6}}{9 π} A / m^{2}$

$ρ = \frac{E}{j} = \frac{250 \times 9 π}{8 \times 10^{6}} = 8.83 \times 10^{- 4} Ω - m$

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