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A potential difference of $30 KV$ is applied across an $X -$ ray tube. Find the minimum wavelength of $X -$ ray generated.

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$7.07 \times 10^{- 2} A$

$7.07 \times 10^{- 10} m$

$4.133 \times 10^{- 11} m$

$4.133 \times 10^{- 10} m$

answer is D.

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Detailed Solution

$λ = \frac{1240}{30000} = 41.3 \times 10^{- 3} nm = 41.3 \times 10^{- 12} m = 4.133 \times 10^{- 11} m$

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