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A potential divider is used to give outputs of 4 V and 8 V from a 12 V source. Which combination of resistances, ( $R_{1}, R_{2}, R_{3}$ ) gives the correct voltages ? $R_{1} : R_{2} : R_{3}$

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2 : 1 : 2

1 : 1 : 1

1 : 1 : 2

2 : 2 : 1

answer is B.

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Detailed Solution

Resistors are connected in series. So current through each resistor will be same

$\Rightarrow i = \frac{{12 - 8}}{{{R_3}}} = \frac{{8 - 4}}{{{R_2}}} = \frac{{4 - 0}}{{{R_1}}} \Rightarrow \frac{4}{{{R_3}}} = \frac{4}{{{R_2}}} = \frac{4}{{{R_1}}}$

$So,\,{R_1}:{R_2}:{R_3}::\;1:1:1$

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