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A potentiometer arrangement is shown in figure. The driver cell has emf e and internal resistance r.
The resistance of potentiometer wire AB is R. F is the cell of emf e/3 and internal resistance r/3. Balance point (J) can be obtained for all finite values of

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R> r/3

R> r/2

R < r/2

R < r/3

answer is A.

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Detailed Solution

Current in AB $I = \frac{e}{R + r}$

Potential difference across $A B = I R = \frac{e R}{R + r}$

To obtain balanced point, $\frac{e R}{R + r} > \frac{e}{3} o r R > r / 2$

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