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A pre-weighed vessel was filled with oxygen at NTP and weighed. It was then evacuated, filled with SO₂ at the same temperature and pressure and again weighed. The weight of oxygen will be

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The same as SO₂

1/2 that of SO₂

Twice that of SO₂

1/4 that of SO₂

answer is B.

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Detailed Solution

At constant temperature and pressure, an equal volume of gas contains an equal number of moles.

$∴ Moles of O_{2} = Moles of {SO}_{2} 1 mole of O_{2} = 32 g 1 mole of {SO}_{2} = 64 g ∴ wt . of O_{2} = \frac{1}{2} that of {SO}_{2}$

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