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A pressure of $10^{6} d y n e / c m^{2}$ is equivalent to

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$10^{5} N / m^{2}$

$10^{4} N / m^{2}$

$10^{7} N / m^{2}$

$10^{6} N / m^{2}$

answer is A.

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Detailed Solution

1 dyne = $10^{- 5}$ newton
$1 c m = 10^{- 2} m, 1 c m^{2} = 10^{- 4} m^{2}$
$10^{6} d y n e / c m^{2} = 10^{6} \times 10^{- 5} / 10^{- 4} = 10^{5} N / m^{2}$

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