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Q.

A primary cell has an e.m.f. of 1.5 V, when short circuited it gives a current of 3A, then the internal resistance of the cell is

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a

4.5 $Ω$

b

2.5 $Ω$

c

0.5 $Ω$

d

2 $Ω$

answer is C.

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Detailed Solution

detailed_solution_thumbnail

When short-circuited, R = 0 $Ω$

$I = \frac{e . m . f}{internal resistance}$

$3 A = \frac{1.5 V}{r} \Rightarrow r = 0.5 Ω$

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