Q.

A prism is set for minimum deviation for light of wavelength  λ1. The angle of minimum deviation D in this case is equal to the angle of the prism. When the prism is set for minimum deviation for another wavelength  λ2, the angle of minimum deviation is 30°. The refractive index of the prism material for λ1 is  3. The refractive index of the prism material for λ2 is

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a

32

b

3

c

22

d

2

answer is B.

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Detailed Solution

For λ1,D=A  n=sinA+A/2sinA/22cosA2=3   A=600
For 

λ2,D'=300,A=600n'=sin600+300/2sin600/2=sin450sin300  n=1/21/2=2

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