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Q.

A prism (m = 1.5) has a refracting angle of 30°. The deviation of a monochromatic ray incident normally on its one surface will be (sin 48° 36’ = 0.75)

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a

22°1’

b

18° 36’

c

20° 30’

d

18°

answer is A.

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Detailed Solution

Question Image

 For surface AC1μ=sin⁡30∘sin⁡e⇒sin⁡e=μsin⁡30∘

⇒sin⁡e=1.5×12=0.75

⇒e=sin−1⁡(0.75)=48∘36′

From figure, δ=e−30∘

=48∘36′−30∘=18∘36′

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