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Q.

A prism of refractive index μ and angle of prism A is placed in the position of minimum angle of deviation. If minimum angle of deviation is also A, then in terms of refractive index A is

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a

sin−1⁡μ2

b

sin−1⁡μ−12

c

2cos−1⁡μ2

d

cos−1⁡μ2

answer is A.

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Detailed Solution

According to prism formula

μ=sin⁡A+δm2sin⁡A2

Here, δm = angle of minimum deviation

A= angle of prism
We have given δm=A

∴μ=sin⁡Asin⁡A/2⇒μ=2cos⁡A2

⇒A=2cos−1⁡μ2

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