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A process is taking place at constant temperature and pressure. Then

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$ΔH = 0$

$ΔH = ΔE$

$ΔH = TΔS$

$ΔS = 0$

answer is B.

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Detailed Solution

$ΔG = ΔH - TΔS$

at constant temperature and pressure $ΔG = 0$

$0 = ΔH - TΔS so ΔH = TΔS .$

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