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A progressive wave moves with a velocity of 36m/s in a medium with a frequency of 200Hz. The phase difference between two particles separated by a distance of 1cm is

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$π$ ^o/9

$π$ /9 rad

40°

20 rad

answer is C.

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Detailed Solution

$∆$ x = 1 cm = 10^-2 m Phase difference $∆ ϕ$ = ?

$Phase difference = \frac{2 π \times ∆ x}{λ}$

$λ = \frac{v}{ν} = \frac{36}{200}$
$∆ ϕ = \frac{2 π x 200}{36} x 10^{- 2} = \frac{π}{9}$

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