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Q.

A projectile can have the same range R for two angles of projection. If t1 and t2 be the times of flights in the two cases, then the product of the two times of flight is proportional to

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a

R

b

1/R

c

1/R2

d

R2

answer is A.

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Detailed Solution

Here t1=2usinαg and t2=2usin90αg(1)

Now    t1t2=4u2g2sinαcosα

We know that

R=u2sin2αg

From eqs. (1) and (2), we get 

t1t2=2RgR

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A projectile can have the same range R for two angles of projection. If t1 and t2 be the times of flights in the two cases, then the product of the two times of flight is proportional to