A projectile has the maximum range of 400m. If it is pushed up smooth inclined plane of angle 30° with the same speed, the distance travelled by it along the inclined plane will be

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50 m

400 m

200 m

100 m

answer is C.

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Detailed Solution

Maximum range is obtained at 45° angle of projection.

$R_{\max} = u^{2} / g \Rightarrow 400 = \frac{u^{2}}{10} \Rightarrow u^{2} = 4000$

Acceleration along inclined plane is $g \sin 30^{0}$ along down the plane.

$0 = u^{2} - 2 (g \times \frac{1}{2}) S$

$\Rightarrow S = 400 m$

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