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Q.

A projectile is fired from the surface of the earth with a velocity of 5 ms-1 and angle θ with the horizontal. Another projectile fired from another planet with a velocity of 3 ms-1 at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in ms-2) is (given g = 9.8 ms-2)

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a

3.5

b

16.3

c

110.8

d

5.9

answer is A.

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Detailed Solution

y = x tan θ - gx22u2 cos2 θ

For equal trajectories for the same angle of projection

        gu2 = constant      9.852 = g'32

         g' = 9.8 ×925 = 3.528 m/s2 = 3.5 m/s2

 

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