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A projectile is fired with a velocity ‘u’ at right angles to an inclined plane which is at an angle ‘ $θ$ ’ with horizontal

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Time of flight is $\frac{2u}{g cos θ}$

The motion of particle along any direction is uniformly accelerated motion

Range on inclined plane is $\frac{{2u}^{2}}{g} t anθsecθ$

Horizontal motion is uniform motion

answer is A, B, D.

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Detailed Solution

${θ = 90}^{0};T = \frac{2usin90}{gcosθ} = \frac{2u}{gcosθ}$ .

$R= ucos90T+ \frac{1}{2} {gsinθT}^{2} = \frac{{2u}^{2}}{g} tanθsecθ$

There is no acceleration in the horizontal direction and the motion will be uniform.

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