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A projectile is moving at $60 m / s$ at its highest point, where it breaks into two equal parts due to an internal explosion. One part moves vertically up at $50 m / s$ with respect to the ground. The other part will move at

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$110 m / s$

$120 m / s$

$130 m / s$

$10 \sqrt{61} m / s$

answer is C.

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Detailed Solution

${(∆ P)}_{x} = 0 M \times 60 = \frac{M}{2} \times v_{x} v_{x} = 120 m / s {(∆ P)}_{y} = 0 \frac{M}{2} \times 50 = \frac{M}{2} \times v_{y} v_{y} = 50 m / s v = \sqrt{v_{x}^{2} + v_{y}^{2}} = 130 m / s$

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