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Q.

A projectile is thrown upward with a velocity v0 at an angle α to the horizontal. The change in velocity of the projectile when it strikes the same horizontal plane is

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a

2v0 sinα vertically upward

b

2v0 sinα vertically downward

c

v0 sinα vertically downward

d

Zero

answer is B.

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Detailed Solution

Δv=aΔt     (As, a = constant)

=(-gj^)2v0sinαg=-2v0sinαj^

i.e. Change in velocity is 2v0 sinα, vertically downwards.

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