A projectile of mass $3 m$ explodes at highest point of its path. It breaks into three equal parts. One part retraces its path, the second one comes to rest. The range of the projectile was $100 m$ if no explosion would have taken place. The distance of the third part from the point of projection when it finally lands on the ground is

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$300 m$

$250 m$

$150 m$

$100 m$

answer is C.

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Detailed Solution

The centre of mass will follow the same path.
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$m x = m \frac{R}{2} + m R$ or $x = \frac{3 R}{2} = \frac{3 \times 100}{2} = 150 m$
The desired distance is $(100 + 150) m$ or $250 m$

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