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Q.

A projectile of mass M is fired so that the horizontal range is 4 km. At the highest point the projectile explodes in two parts of masses M/4 and 3M/4 respectively and the heavier part starts falling down vertically with zero initial speed. The horizontal range (distance form point of fring) of the lighter part is :

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a

2 km

b

16 km

c

1 km

d

10 km

answer is C.

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Detailed Solution

XCOM ​= m1x1+m2x2m1+m2


i.e. R=Mx4+3M4×R2M


⇒x = 10 Km

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