A projectile of mass M is fired so that the horizontal range is 4 km. At the highest point the projectile explodes in two parts of masses M/4 and 3M/4 respectively and the heavier part starts falling down vertically with zero initial speed. The horizontal range (distance form point of fring) of the lighter part is :

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

2 km

16 km

1 km

10 km

answer is C.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

X_COM= $\frac{m_{1} x_{1} + m_{2} x_{2}}{m_{1} + m_{2}}$

i.e. R= $\frac{(\frac{Mx}{4} + \frac{3 M}{4} \times \frac{R}{2})}{M}$

⇒x = 10 Km

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test