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A projectile of mass M is fired so that the horizontal range is 4 km. At the highest point the projectile explodes in two parts of masses M/4 and 3M/4 respectively and the heavier part starts falling down vertically with zero initial speed. The horizontal range (distance form point of fring) of the lighter part is :

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2 km

16 km

1 km

10 km

answer is C.

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Detailed Solution

X_COM= $\frac{m_{1} x_{1} + m_{2} x_{2}}{m_{1} + m_{2}}$

i.e. R= $\frac{(\frac{Mx}{4} + \frac{3 M}{4} \times \frac{R}{2})}{M}$

⇒x = 10 Km

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