Q.

A projectile with speed 50 ms1 is thrown at an angle of 60o with the horizontal. The maximum height that can be reached is (acceleration due to gravity = 10 ms2)

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a

85.00 m

b

93.75 m

c

90.75 m

d

70.00 m

answer is D.

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Detailed Solution

Speed of projectile, u=50ms1  
Angle of projection, θ=60o 
g=10ms2 
Maximum height attained by projectile,
H=u2sin2θ2g=502×sin260o2×10=2500×(32)220=125×34=3754=93.75m 

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