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Q.

A property valued at Rs. 30000 will depreciate Rs. 1380 the first year, Rs. 1340 the second year, Rs. 1300 the third year, and so on. What will the depreciation during the eight years?

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a

Rs. 1150

b

Rs. 1200

c

Rs. 1100

d

Rs. 1250

answer is C.

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Detailed Solution

It is given a property valued at Rs. 30000 will depreciate Rs. 1380 the first year, Rs. 1340 the second year, Rs. 1300 the third year, and so on.
The value of depreciation each year can be written as shown below,
1380, 1340, 1300, ……
From this, we get that the numbers are in an AP with first term 1380 and common difference –80.
So, we get
a = 1380, d = –40.
We know that

n^{th}

term of an AP is given as,

a_{n} = a + (n - 1) d

So, the value deprecated in the 8th year will be,

a_{8} = 1380 + (8 - 1) \times (- 40)

\Rightarrow a_{8} = 1380 + 7 \times (- 40)

\Rightarrow a_{8} = 1380 - 280

\Rightarrow a_{8} = 1100

Therefore, the depreciation in the value of property will be, Rs.1100.
Hence, the correct option is 3.

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A property valued at Rs. 30000 will depreciate Rs. 1380 the first year, Rs. 1340 the second year, Rs. 1300 the third year, and so on. What will the depreciation during the eight years?