A proton and an electron travelling along parallel paths enter a region of uniform magnetic field, acting perpendicular to their paths. Which of them will move in a circular path with higher frequency?

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Detailed Solution

Frequency of revolution of a particle,
$\begin{array}{l} f = \frac{Br}{2 πm} \\ f \propto \frac{1}{m} \end{array}$
Since mass of electron is less than that of proton, therefore, its frequency of revolution will be higher than that of proton.

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